There are 45 factors of 3600 of which 3600 itself is the biggest factor and its prime factors are 2, 3, 5 The sum of all factors of 3600 is 12493.
3600=2×2×2×2×3×3×5×5=24×32×52.
Sum of Factors of 3000: 9360
What Are the Factors of 3000?
Since each of these 24 pairings is a factor of 3,600, we have 24 factors of 3600 that are divisible by 6.
Number of factors which are perfect squares =3×2×2=12.
So, Factors of 3600 are 2, 4, 6, 8, 10, 12, 16, 18, 20, 24, 30, 36, 40, 48, 50, 60, 80, 90, 96, 100, 120, 150, 160, 180, 200, 240, 300, 360, 400, 480, 600, 720, 900, 1200, 1800 and 3600. So, there are 35 factors.
A perfect number is a positive integer that is equal to the sum of its factors excluding the number itself. For example, 6 is a perfect number because when we add all its factors except 6, we get, 1 + 2 + 3 = 6. We get the sum as the number itself. Therefore, 6 is a perfect number.
What is the Sum of all the Factors of 10? Since all factors of 10 are 1, 2, 5, 10 therefore, the sum of its factors is 1 + 2 + 5 + 10 = 18.
Its pair factors are (1, 24), (2, 12), (3, 8), and (4, 6). The prime factorisation of 24 gives 2 x 2 x 2 x 3 = 23 x 3, where 2 and 3 are the prime factors of 24. The sum of factors of 24 is 60.
Sum of Factors of 2240: 6096
What Are the Factors of 2240?
There are total 40 factors of 3240, of which 2, 3, 5 are its prime factors. The sum of all factors of 3240 is 10890.
The sum of all the factors of 1000 is 2 4 − 1 2 − 1 × 5 4 − 1 5 − 1 = 2340 \frac{ 2^4 - 1 } { 2 - 1 } \times \frac{ 5^ 4 - 1 } { 5-1 } = 2340 2−124−1×5−154−1=2340.
Consider 60 multiplied by 60 itself or – 60 multiplied by – 60. The product is 3600. Here 3600 is called the perfect square number and ±60 is its square root.
There are 9 odd divisors of 3600.
The prime factorization of 3600 using exponents is 2 4 ∗ 3 2 ∗ 5 2 .
Solution: We know the factors of 5 are 1 and 5. The sum of all the factors of 5 = 1 + 5 = 6.
Negative factors of 300 are -1, -2, -3, -4, -5, -6, -10, -12, -15, -20, -25, -30, -50, -60, -75, -100, -150, and -300. Sum of factors of 300 is 868.
1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 18, 20, 24, 30, 36, 40, 45, 60, 70, 90, 120, 180, and 360. Clearly, we can see that, there are 24 factors of 360. Hence, the number of factors of 360 is 24 and the sum of all factors is 1170. are called Prime numbers.
Explanation: The prime factors of 720 are: 24 × 32 × 51. The required sum of factors would be: (1 + 2 + 22 + 23 + 24 )(1 + 3 + 32 )(1 + 5) = 31 × 13 × 6 = 2418.
Ans 4: The sum of factors of 120 is 360. Que 5: Find the common factor of 60 and 120. Ans 5: We need to first find the factors of 60 and 120. Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60.
The sum of all factors of 520 is 1260.
Hence, the factors of 3500 are 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, 3500.
Therefore, the number of even factors of 36000 that are divisible by 9 but not by 36 = Number of factors of 36000 with exactly one factor of 3 and no more than one factor of 2^2 = 24. Hence, the correct answer is option B (4).
11 is a prime number because the only factors of 11 are 1 and 11 ( 1 × 11 = 11 ). No other whole numbers can multiply together to make 11.